通过CaO-SiO₂-CaF₂三元系的烧结实验，结合光学显微镜观察和X射线衍射分析，对含氟矿烧结过程中枪晶石(Ca₄Si₂O₇F₂)的生成及其与铁酸钙(CaFe₂O₄)的作用进行了研究. 结果表明，1050℃空气气氛下烧结时，CaO和SiO₂先发生反应生成Ca₂SiO₄，再与SiO₂和CaF₂发生反应生成枪晶石；CaFe₂O₄和枪晶石在1220℃下烧结时，都可稳定存在，自由态SiO₂是含氟矿烧结过程中CaFe₂O₄分解的关键因素，SiO₂与CaFe₂O₄反应生成Ca₂SiO₄和中间产物Ca₂Fe₂₂O₃₃，随SiO₂含量增加，Ca₂Fe₂₂O₃₃量逐渐减少，Fe₂O₃量逐渐增加；SiO₂含量为6.0%(w)时，Ca₂Fe₂₂O₃₃消失，最终产物为Ca₂SiO₄和Fe₂O₃；生成的Ca₂SiO₄会与SiO₂和CaF₂发生反应生成枪晶石，抑制CaFe₂O₄生成. CaFe₂O₄、枪晶石和CaF₂在1200℃下烧结时三者不发生反应.

Combining analysis of XRD and optical microscopy (OM), the experiments sintered in CaO-SiO₂-CaF₂ system were carried out to investigate the formation of cuspidine (Ca₄Si₂O₇F₂) and the action on calcium ferrite (CaFe₂O₄). The results showed that when the sample was sintered at 1050℃, Ca₂SiO₄ was generated first by the reaction of CaO and SiO₂, then the Ca₂SiO₄ reacted with CaF₂ and SiO₂ to form the Ca₄Si₂O₇F₂. Ca₄Si₂O₇F₂ and CaFe₂O₄ both can coexist stably at 1200℃. The existence of free SiO₂ is the key factor to degradation of CaFe₂O₄ during the sintering process of fluorine-containing ore. SiO₂ reacted with CaFe₂O₄ to generate Ca₂SiO₄ and Ca₂Fe₂₂O₃₃, but the amount of Ca₂Fe₂₂O₃₃ decreased with increase of SiO₂, up to disappearance of Ca₂Fe₂₂O₃₃ when SiO₂ was 6.0%(w), and then formed Ca₂SiO₄ and Fe₂O₃. Finally Ca₂SiO₄ reacted with CaF₂ and SiO₂ to form Ca₄Si₂O₇F₂. An interesting phenomenon is found that CaF₂ was added into the equivalent amount mixture of Ca₄Si₂O₇F₂ and CaFe₂O₄, the three also coexisted stably at 1200℃.